MATH SOLVE

4 months ago

Q:
# plz help me i make you the bralnlyiest personOn a flight home from college, Elizabeth had to pay $20 to check her bag, plus $8 for every pound over the weight limit. On the flight back to college, she paid $26 to check her bag and $5 for every pound over the weight limit. If the total baggage fees were the same for each trip: 1. Write a system of equations to describe the situation. 2. How much over the weight limit was Elizabeth’s bag? 3. What was the baggage fee paid toeach airline? PLZ ANSWER FAST

Accepted Solution

A:

1. If the total baggage fees were equal, you would have to equate the two situations. Suppose x is the weight above the limit on the flight home, while y is the weight above the limit on the flight back to college. Then, the equation would be:

20 + 8x = 26 + 5y

Now, we have two unknowns, but only one independent equation. This is unsolvable unless we make an assumption. Suppose the excess weight for both trips are the same such that x=y, then,

20 + 8x = 26 + 5x

2. Then, we solve for x.

8x - 5x = 26 - 20

3x = 6

x = 6/3 = 2 lb

Thus, Elizabeth's bag was 2 lb over the weight limit.

3. The total baggage fee would then be:

20+8(2) = 26 + 5(2) = $36

20 + 8x = 26 + 5y

Now, we have two unknowns, but only one independent equation. This is unsolvable unless we make an assumption. Suppose the excess weight for both trips are the same such that x=y, then,

20 + 8x = 26 + 5x

2. Then, we solve for x.

8x - 5x = 26 - 20

3x = 6

x = 6/3 = 2 lb

Thus, Elizabeth's bag was 2 lb over the weight limit.

3. The total baggage fee would then be:

20+8(2) = 26 + 5(2) = $36