simplify u^2+3u/u^2-9A.u/u-3, =/ -3, and u=/3B. u/u-3, u=/-3
Accepted Solution
A:
The correct answer is: Answer choice: [A]: __________________________________________________________ → "[tex] \frac{u}{u-3} [/tex] " ; " { u [tex] \neq [/tex] ± 3 } " ;
→ or, write as: " u / (u − 3) " ; {" u ≠ 3 "} AND: {" u ≠ -3 "} ; __________________________________________________________ Explanation: __________________________________________________________ We are asked to simplify:
[tex] \frac{(u^2+3u)}{(u^2-9)} [/tex] ;
Note that the "numerator" —which is: "(u² + 3u)" — can be factored into: → " u(u + 3) " ;
And that the "denominator" —which is: "(u² − 9)" — can be factored into: → "(u − 3) (u + 3)" ; ___________________________________________________________ Let us rewrite as: ___________________________________________________________