Triangle ABC is translated 2 units right and 5 units down to form triangle A′B′C′. This triangle is then translated 5 units right and 4 units up to form triangle A″B″C″. If vertex A is at (-4, 2), what are the coordinates of vertex A″?

Answer:The coordinates of vertex A" is (3 , 1)Step-by-step explanation:* Lets revise The translation of a point- If the point (x , y) translated horizontally to the right by h units  then the new point = (x + h , y)- If the point (x , y) translated horizontally to the left by h units  then the new point = (x - h , y)- If the point (x , y) translated vertically up by k units  then the new point = (x , y + k)- If the point (x , y) translated vertically down by k units  then the new point = (x , y - k)* Now lets solve the problem∵ Δ ABC has a vertex A = (-4 , 2)∵ The Δ ABC is translated 2 units right and 5 units down to form    triangle A′B′C′- From the rule above the x coordinate id added by 2 and the  y-coordinate is subtracted by 5∴ A' = (-4 + 2 , 2 - 5) = (-2 , -3)∴ The image of vertex A is A' = (-2 , -3)∵ Δ A'B'C' is then translated 5 units right and 4 units up to form    triangle A″B″C″- From the rule above the x coordinate is added by 5 and the  y-coordinate is add by 4∴ A" = (-2 + 5 , -3 + 4) = (3 , 1)* The coordinates of vertex A" is (3 , 1)